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### Best Answer Jim Bob says

I tried to find expressions that used the digits in ascending order:

(1+2+3+4+5)x6 - 7 + 8 + 9 = 100

(1+2+3+4)x5 + 67 - 8 - 9 = 100

-1 + 2 + 3 + 4x5x6 - 7 - 8 - 9 = 100

Found three more expressions:

(1+2+3+4)x((56/7)/8 + 9) = 100,

(((1+2)^3)x4 - 56/7)x(-8+9) = 100, and

123 - 45 - 67 + 89 = 100.

It was a nice challenge.

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### paxwill says

Here are some I came up with:

89 + 12 + (7!/6!) - (5!/4!) - 3 = 100

(1 + 7^2)x(34/(8 + 9))x(5 - 6) = 100

(9 + (48/6) - 7)^(32^(1/5)) = 100

I hope I didn't make any arithmetic errors!

Can I add one more? (72/(3+4+5))x19 - 8 - 6 = 100

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### I'M BANNED Y'ALL!!!!!!!!!! says

Going for simplicity

968 - 547 - 321 = 100

986 - 754 - 132 = 100

896 - 375 - 421 = 100

I think allowing factorials and exponents makes it too easy, and 100 is perhaps too low of a target. But it's interesting to see how convoluted the expressions can get.

Well, you can always try to challenge yourself as you just did by restricting yourself to a smaller set of operations.