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# A mom has twin daughters and a son who all have the same birthday. One year, on their birthday,

the mom notices that exactly 5 years from now the product of their three ages will be 6 times the current product. And exactly 10 years from now, the product of all their ages will be 18 times what it currently is. Assuming whole number ages (since it's their birthday), who is older? The daughters or the son?

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82

3 years ago
|  Comment
• TR Smith (calculus-geometry) 3 years ago

Thanks and good explanation.

87

### DreamerMeg says

3 years ago
|  Comment
• TR Smith (calculus-geometry) 3 years ago

Meg, you can solve it any way you like, and it's definitely not cheating to use a solving tool. The hardest part is probably setting up the equations. :)

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### I'M BANNED Y'ALL!!!!!!!!!!(tussin) says

3 years ago
|  Comment
• TR Smith (calculus-geometry) 3 years ago

Good point, that changes everything.

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### TinaAtHome says

3 years ago
|  Comment
• TR Smith (calculus-geometry) 3 years ago

This problem is correctly stated. The twin daughters are not the same age as the son, though they all share a common birthday as noted in the original statement of the problem. :)