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# A mother has four children under the age of 18, all of different ages. She notices that one year

from now, the product of their four ages will be exactly twice the current product of their four ages. Can you find TWO possible solutions sets for the children's current ages? There are at least nine possible solution sets. (Hint: Think of the prime factors.)

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### paxwill says

3 years ago
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• Sid Kemp (SidKemp) 3 years ago

I found the last one: 3, 5, 8, 9! 3*5*8*9 = 1080, *2 = 2160 = 4*6*9*10. I made a list of all we found, 4 starting with 2, 3 starting with 3, and one other. and figured the last one had to start with 3, and hunted it down.

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### Sid Kemp(SidKemp) says

3 years ago
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• Sid Kemp (SidKemp) 3 years ago

I found one more set, 2, 7, 12, 13, with the help below from bubba-math and tussin. Thanks to all three of you (Calculus-Geometry included) for enjoyable brain-strain this Thanksgiving weekend.

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3 years ago
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### I'M BANNED Y'ALL!!!!!!!!!!(tussin) says

3 years ago
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• Jim Bob (bubba-math) 3 years ago

You're right, thanks for correcting that.

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