# Prepare for JEE ADVANCED, 2013: Tough problems on equivalent capacitance and resistance

Updated on January 31, 2013 ## Why solve problems on equivalent capacitance and resistance?

Such problems involving equivalent resistance and capacitance have been regularly set in previous IITJEE and AIEEE exams in some form or the other. So practice of such problems is a must before appearing in similar tests. Moreover, attempts to solve such problems provide a good understanding of electrical circuits and help in solving other circuit problems too.

## Problem 1:

Find the equivalent capacitance across the principal diagonal AE of the mesh cube shown in fig. 1 which has a resistance ‘R’ in each side.

## Solution:

There are many techniques to solve this problem but the simplest one will be described here.

Let us extend the terminal A and E and connect them to a voltage source ‘V’ and also assume that a current 6A passes in the main circuit as shown in fig 2.

Now, at point A the main current of 6 A divides into 3 branches and due to symmetry we can understand that each branch will carry a current of 2A (Branches AE, AB and AD).

Now the branch AB supplies current to BF and BC. Again by symmetry we can understand that BF and BC will carry currents of 1A each. Branches BF, AC, EF, EH,DH and DC are all 1A branches.

The 1A currents in these branches combine to re-create 2A currents in branches HG, FG and CG which in turn combine to re-create the main 6A current.

Now, let us apply KVL to the loop ADCG-V, we get,

V=2R+R+2R

ð V=5R

ð Since, V=6 R EQ. where R Eq= Total resistance of the cube mesh, we have,

6 R Eq=5R

Therefore, R Eq=(5/6)R

Ans= 5R/6

## Problem 2:

Find the equivalent capacitance across the points ‘P’ and ‘Q’ in the network of the adjacent figure.

## Solution:

Such problems which involve capacitances or resistances difficult to understand whether they are in parallel or series, can be solved by a method of writing terminal voltages and then grouping the capacitances with similar voltage differences together.

In figure 2, the end voltages have been assumed as v1, v2, v3. Mark that ends of capacitors joined by a conductor will have same voltage.

## Grouping together capacitors of same end voltages

If we group together capacitances with same end voltages we get the following :

End voltages v1 and v2: 3 number of capacitors= 3 capacitors in parallel=3C

End voltages v2 and v3: 2 number of capacitors=2 capacitors in parallel=2C

End voltages v2 and v4: 1 number of capacitor= C

## Drawing the final diagram and calculating equivalent capacitance

Now, the diagram can be redrawn as in figure 3.

Since we have to find the equivalent capacitance between P and Q, we take the path PSQ and neglect the part SR.

This means 3C and C in series.

Therefore, Equivalent Capacitance, Ceq=(3CXC)/(3C+C)=3C/4

Ans= 3C/4

## Some points to be noted

I shall advise you all to first attempt to solve the questions yourself. Even if you find them difficult, try hard. Such attempts will help you in the long run.

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• rajat

2 years ago

How to find equivalent capacitance of unbalanced Wheatstone bridge?

• Gunjan

2 years ago

I need more questions based on equivalent resistance

• Abhay

2 years ago

Sir plz give some more difficult question I wanna challenge my mind and concept on this topic

• Tanya

4 years ago

Sir can you provide some difficult questions

• Raghu

5 years ago

sir...can u please explain how fig 3 came from fig2

• anshika

5 years ago

what are the techniques to solve numericals of capacitance of series parallel connection

• dhruv

5 years ago

sir i m feeling problems in doing the questions of effective resistance in combined series and parallel systems ...please help me out by providing some short tricks and some examples

i will be very thankful to you

• vishal

6 years ago

HOW TO USE THIS METHOD IN MORE COMPLICATED QUESTIONS WHEN CAPACITOR ARE NOTALIGNED ON ONE LINE

• vishal

6 years ago

HOW TO USE THIS METHOD IN MORE COMPLICATED QUESTIONS WHEN CAPACITOR ARE NOTALIGNED ON ONE LINE

• maxxo

6 years ago

thanks..

• AUTHOR

RAJESH CHANDRA PANDEY

7 years ago from India

@Aman,

Though I don't promise but time permitting I shall definitely try.

Thanks

• AMAN CHUNARA

7 years ago

SIR, i want to clear out the concepts of GAUSS THEOREM AND MAGNETIC EFFECTS OF CURRENT...PLZ HELP ME OUT BY PROVIDING NOTES AND SOME QUESTIONS...!!!!

NEED TRUE HELP

• AUTHOR

RAJESH CHANDRA PANDEY

7 years ago from India

@akhil

OK I shall try to provide a sum or two. Thanks

• AKHIL

7 years ago

Sir i am preparing for IITJEE

i would like you to explain the concept of Grounding the endpoints of the circuit and its effect while determining the current in the circuit with the help of some tough sums.

THANK YOU

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