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# GMAT Preparation Math Review Geometry Circle Solutions Part 2

## 1.

If we draw red lines we will have the right triangle with a side of r, 5-r and 5+r. We can apply Pythagorean Theorem.

5^{2 }+ (5-r)^{ 2} = (5+r)^{ 2}

r=1.25

**Correct choice is B**

## 2.

If we draw red lines we will have the right triangle with a side of 2, 2 and 2+r. We can apply Pythagorean Theorem.

2^{2 }+ 2^{ 2} = (2+r)^{ 2}

r=2√2 - 2

**Correct choice is C**

## 3.

If we draw red lines we will have the right triangle with a side of 4 and 4.

A(Shaded) = 2 *( A(1/4 of Circle Sector)-A(Triangle in red))

= 2(1/4 π 42^{} – (1/2) 4 4 )

= 8π – 16

**Correct Choice is D**

## 4.

If we draw red lines we will have the right triangle with a side of 4 and 4.

A (Shaded) = 2(A(square) - A(1/4 of Circle Sector)) = 2(4*4 - (1/4 * π * 4^{2}))

= 32-8π

**Correct choice is B**

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