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GMAT Preparation Math Review Geometry Circle Solutions Part 2

Updated on May 28, 2012

1.

If we draw red lines we will have the right triangle with a side of r, 5-r and 5+r. We can apply Pythagorean Theorem.

52 + (5-r) 2 = (5+r) 2

r=1.25

Correct choice is B





2.

If we draw red lines we will have the right triangle with a side of 2, 2 and 2+r. We can apply Pythagorean Theorem.


22 + 2 2 = (2+r) 2

r=2√2 - 2

Correct choice is C




3.

If we draw red lines we will have the right triangle with a side of 4 and 4.

A(Shaded) = 2 *( A(1/4 of Circle Sector)-A(Triangle in red))

= 2(1/4 π 42 – (1/2) 4 4 )


= 8π – 16

Correct Choice is D




4.

If we draw red lines we will have the right triangle with a side of 4 and 4.

A (Shaded) = 2(A(square) - A(1/4 of Circle Sector)) = 2(4*4 - (1/4 * π * 42))

= 32-8π


Correct choice is B

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