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Factoring Exponents

Updated on August 5, 2017

There are multiple methods for factoring an expression with exponents.

If you are on this page you are either

  1. Trying to factor exponents directly (ex x2 + x)
  2. Trying to factor expressions with exponents (ex: x2  - 16)
This hub covers both, in the order specified

Note: Altough you can factor variables with exponents, you cannot factor the exponents themselves. For example: you can factor the x in (x2+2x), but you cannot factor the 2 in x2 + y2


Before explaining how to factor exponents, let's review some terms.

Base: The base is the variable or number in question. 4x2

Exponent: An exponent is the power of a base. It implies how many times that base is multiplied by itself. 4x2

Coefficient: A number or variable that accompanies a base, but isn't an exponent. 4x2

Term: A base (that may or may not be accompanied by a coefficient or exponent). 4x2

Monomial: An expression of a single term. 4x2

Polynomial: Multiple terms that are added or subtracted. 8x3 - 4x2 - 2x + 4

Binomial: A polynomial of exactly two terms. 2x + 4

Trionomial: A polynomial or exactly three terms. 4x2 - 2x + 4

Factoring polynomials within exponents

If you have a single base whose exponent happens to be an expression, you can indeed start factoring exponents. If the terms are separated by a +, you make another factor with the same base and just move over the term that had been separated by +. If the term was sepatated by a - sign, you do the same but instead of multiplication, you use division.


  • x2y + 2 becomes (x2y) (x2)
  • x y-2 becomes (xy) / (x2)
  • 3x9x^2 - 16 becomes (3x9x^2) / (3x16)
  • (The above example can also become 3x(3x-4)(3x+4) if you use the difference of squares method mentioned below, though this probably won't be very useful. I just want to point out that the rules for factoring polynomials also apply if the polynomial is within an exponent - should you choose to do so)

Common Factors Used for Factoring Exponents

One way to factor is to see what two sets of terms share


  • Given the expression: 2x2 + 2y
  • 2x2 are factors 2 * x * x
  • 2y are factors 2 * y
  • They have 2 in common

So what do I do with that?

You take the common factor(s) aside. You then put the original terms in a parenthesis and divide the common factors from each term. Put the parenthesis and the set-aside factors together.Example:

  • We established that 2x2 and 2y have 2 in common
  • 2 is set aside
  • (2x2 + 2y) divided by 2 becomes (x2 + y). Set aside.
  • Put both back together to make 2 (x2 + y)

NOTE: The common factors don't have to be numbers! Variables can be common factors too! so you can factor them out too. When you take out a common variable, you reduce the original exponent by 1.


  • 3x3 + 2x both have x in common. They become x ( 3x2 + 2)
  • x3 + x2 both have x in common as well. However, notice how the exponents go to 3 and 2? That means your variable in common goes up to 2. So in reality, x2 is their common factor. This factors into x2 (x + 1)

Factoring by Difference of the Squares

If you have a polynomial where both terms are squares and one of them is accompanied by a negative/minus sign, you can use difference of two squares. This can be used for factoring exponents that are even.


  • x2 - 9 is (x)2 - (3)2
  • -4x2 + 1 can be rewritten as 1 - 4x2, which is therefore (1)2 - (2x)2

Ok, but what do I do with it?

You can make it into two factors by using the numbers within the () above and putting them as two terms. In one factor these terms are separated by -, and in the other, they are separated by +.


  • We already established that -4x2 + 1 can be rewritten (1)2 - (2x)2. Therefore it factors into (1 - 2x) (1 + 2x)
  • We also established that x2 - 9 is (x)2 - (3)2. This factors into (x - 3) (x + 3)
  • 9x2 - 16 is (3x)2 - (4)2. Therefore it factors into (3x - 4) (3x + 4)

Trinomial Factorization

Trinomials of power 2 can be factored using their own special way.

Trinomials of power 2??

Yes, trinomials where the highest exponent is 2. Generally trinomials that look like ax2 + bx + c.


  • x2 + 4x + 2
  • y2 + 7y + 6
  • x2 - x - 6
  • 2x2 + 9x + 7 (polynomials like this would need the eyeglass method in order to yield the answer of (x + 1)(2x + 7) )

Going over Trinomial factorization, as well as the eyeglass method, would take far too long for this one hub so here is a video to help you get going!

Factoring Trinomial Video

Factoring polynomials of degrees bigger than 3

Factoring a polynomial of degree bigger than 3 can be difficult, unless you're lucky enough to factor out some of that degree. (example x^3 + x^2 + x can be factored into x ( x^2 + x^1 +1) and therefore both of the factors would be in degrees less than 3. So further factoring using the basic techniques mentioned above would work)

If you aren't so lucky, chances are you won't be able to factor using regular techniques. You will need to do either factor or synthetic division (both of which allow you to divide out binomial factors) by taking guesses on what you think one of the factors is. Using a graphing calculator might help you find the zeroes of the equation, which in turn can be used to help you do either factor or synthetic division.

Got Questions?

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      4 years ago

      A pllisangey rational answer. Good to hear from you.

    • profile image


      4 years ago

      I appreciate your kind and geeunors advice a lot!. I have been trying it hardly and did not get those amazing results!. It is nice to see that you got my comment in a good way!God bless you!VA:F [1.9.10_1130]please wait VA:F [1.9.10_1130](from 0 votes)


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