what is the mass of silver nitrate in 145.0 ml of a 4.31 M AgNO3 solution?
No. of moles of substance in aqueous = MV/1000M = Molarity or concentrationV = volume in mLHence, No. of moles of AgNO3 = (4.31 x 145 ) / 1000= 0.625 mol= 0.625 x RMM (AgNO3) grammass = 0.625 x 169.88 g/mol= 106 gHope this helps!
Silver Nitrate has Mass? I didn't even know that Silver Nitrate was Catholic!
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