Six times the sum of first n terms of the sequence 1, 1, 2, 3, 5, 8, 13, 21, 34

  1. pemekwulu profile image60
    pemekwuluposted 7 years ago

    Six times the sum of first n terms of the sequence 1, 1, 2, 3, 5,  8, 13, 21, 34, 55... is equal...

    to 858.  Find n and list the numbers of this set.

  2. simeonvisser profile image84
    simeonvisserposted 7 years ago

    You are told that six times something is 858. So we can find that something by dividing 858 by 6 = 143. You can now generate the sequence of numbers to determine what n needs to be.

  3. profile image0
    Butch Newsposted 7 years ago

    You have provided the sequence in the question.  n=10

 
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