How do you do square root?

1. 76

   DzyMsLizzyposted 11 years ago

   How do you do square root?
   
   Sometimes, the answer is obvious, such as 3 being the square root of 9.  However, I was never able to understand how the square root operation is any different from regular division, given less obvious numbers.  Such as, how would you figure the square root of, say, 43,560. ??
   (That happens to be the square footage of an acre, and I need the root to know how many linear feet down one side of an acre, for my model train layout.)

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2. 78

   Attikosposted 11 years ago

   I trim it on four sides using a sharp knife. You can square a potato in under thirty seconds that way.

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   1. 66

      Kiwi Maxposted 11 years agoin reply to this

      

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3. 66

   Kiwi Maxposted 11 years ago

   Here's another way of thinking about square roots...
   
   what number if multiplied by itself would give 43,560? The answer comes to..."types square root of 43,560 into Google"...208.71!
   
   So if you multiply 208.71*208.71 that would give you a number very close to 43,560!
   
   I say "very close" instead of "exact" because I rounded

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4. 72

   Twilight Lawnsposted 11 years ago

   Don't concern yourself with the 43,560 which is the  square footage of an acre.  This is irrelevant and does not work out as a square root without decimals places.
   I do have the method in my mind and can work out simple square roots of numbers into the mid thousands, "in my head", but although  I was a Maths teacher, I would have difficulty explaining it to you without a "hands on" approach.
   It is so much easier to show and to guide through in person, than to give a written explanation, and setting it into an e-mail or HubPage would be very confusing, perhaps.
   I know HP don't like to have links and URLs in answers, so until you have it deleted by the HubPolice, please accept this and I hope it  works for you.
   http://www.homeschoolmath.net/teaching/ … orithm.php
   Please go to the subsection which deals with "Finding square roots using an algorithm"

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