This is a homework assignment for my colleague's daughter at the uni. We can't solve it. Can someone help?
The big triangle is a prism.
Link has bigger image.
The 90° angle in the middle of the prisma, between X und Z does not look at all like 90°... is it just a rough drawing or are maybe some of the data wrong?
EDIT: I just realised... is this supposed to be a 3D drawing? Then the "weird" 90 degree angle would make sense
Just watch this 14min video about snell's law, that's all you need to know
http://www.khanacademy.org/video/refrac … st=Physics
In your case n=1.58, now you should be able to solve it
I guess this is 3D drawing coz according to physics opposite anglesshould be same. So according to the prism Y should be equal to Z and hence siny/sinz should be equal to one. But it it is not ,according to the data you gave.
I guess this needs some higher physics analyst
I think it's just a sketch and not detailed, I have dealt with thousands of incorrect sketches even on the highest level of my physics studies Sometimes Profs or their assistants are just too lazy to not only put some new numbers there every year but also to redraw the sketches
Oh and siny/sinz doesn't need to be 1 necessarily! Only when light travels in vacuum! If the prism is denser (which it is of course) n>0 ! n=1.58 suggests that the prism might be made out of Polycarbonate
Since opposite angles must be same Y must be equal to 45+z(look carefully on that deviated angle)
Now I guess in that internal triangle,which you mentioned 90 degrees and if it is correct, the other angles must be 45 and 45 and that implies x must be 45.
I guess am not correct 100% but have a look on this solution!
Just glancing, it looks like an equilateral triangle, making X = 60 deg. Now that you know X you can use Snell's law:
ni*sin(i)=nI*sin(I) to solve for y.
Just make sure not to confuse the ray bending toward the normal. Additionally, I assume air is ni=1.
All I remember from that bygone era is Chief soh cah toa.
Copyright © 2018 HubPages Inc. and respective owners. Other product and company names shown may be trademarks of their respective owners. HubPages® is a registered Service Mark of HubPages, Inc. HubPages and Hubbers (authors) may earn revenue on this page based on affiliate relationships and advertisements with partners including Amazon, Google, and others.
|HubPages Device ID||This is used to identify particular browsers or devices when the access the service, and is used for security reasons.|
|Login||This is necessary to sign in to the HubPages Service.|
|HubPages Traffic Pixel||This is used to collect data on traffic to articles and other pages on our site. Unless you are signed in to a HubPages account, all personally identifiable information is anonymized.|
|Remarketing Pixels||We may use remarketing pixels from advertising networks such as Google AdWords, Bing Ads, and Facebook in order to advertise the HubPages Service to people that have visited our sites.|
|Conversion Tracking Pixels||We may use conversion tracking pixels from advertising networks such as Google AdWords, Bing Ads, and Facebook in order to identify when an advertisement has successfully resulted in the desired action, such as signing up for the HubPages Service or publishing an article on the HubPages Service.|