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### Best Answer Ben Evans says

I haven't been back in awhile and I saw this was not solved so I decided to solve it. It really looks a lot harder than it is.

x-x0=1/2at^2 (there is no initial velocity in the y direction)

-1 meter=1/2(-9.8)(m/s^2)t^2

1 meter=1/2(9.8)(m/s^2)t^2

t^2=1/4.9 s^2

t=(1/4.9)^1/2 s=0.45 s

The horizontal distance traveled is 2(.5m)=1 m

So the initial velocity is 1m/0.45 s=2.21 m/s

Well done! When we understand the principle of independence of motion, this is an easy task indeed. Thus, this is the minimal velocity. The second minimal velocity we obtain when the ball once hit the right wall and twice the left one...

### Is a really great guy says

Seriously. Have you enhanced the original Lysergic Acid Diethylamide formula?