If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in t

  1. pemekwulu profile image60
    pemekwuluposted 8 years ago

    If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in terms of b and c.

    Fibonacci numbers are numbers of the form:  1, 1, 2, 3, 5, 8, 13, 21, 34, x, y, x+y.............

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  2. pemekwulu profile image60
    pemekwuluposted 7 years ago

    Given: a^2 + 4bc = 64 for three specific Fibonacci numbers a, b, and c.

    a^2 + 4bc = 64

    Transposing terms we have:

    a^2 = 64 - 4bc.

    Taking the square root of both sides we have:

    a = ?(64-4bc)

    = (?4).?(16-bc) = 2?(16-bc).

    Answer : a = 2?(16-bc)

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    Comments from the author:

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    I am very sorry that it took me much time to get back to this question after it was posted about two months ago.

    If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in terms of b and c

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