If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in terms of b and c.

Fibonacci numbers are numbers of the form: 1, 1, 2, 3, 5, 8, 13, 21, 34, x, y, x+y.............Given: a^2 + 4bc = 64 for three specific Fibonacci numbers a, b, and c.

a^2 + 4bc = 64

Transposing terms we have:

a^2 = 64 - 4bc.

Taking the square root of both sides we have:

a = ?(64-4bc)

= (?4).?(16-bc) = 2?(16-bc).

Answer : a = 2?(16-bc)

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Comments from the author:

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I am very sorry that it took me much time to get back to this question after it was posted about two months ago.

If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in terms of b and c

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