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I know that this is not a homework forum, but I want to help a student who has difficulties, which I could not solve some, in this particular subject. It would be great if anyone can help.
Question: 3.9g of an element X reacts with oxygen gas to form 4.7g of an oxide X2O (X under-script O). The relative atomic mass(Ar) of X is_______?
Thank you once again.
The relative atomic mass of the element is 39 (it's potassium, FWIW).
3.9 g of X reacts with 0.8 g of oxygen (since 4.7 - 3.9 = 0.8)
Get rid of the decimal points by multiplying by 10 on each side.
This means that 39 g of X reacts with 8 g of oxygen.
Handily enough, the atomic mass of oxygen is 16, which is 8 x 2.
Therefore to react with 16 g (one mole) of oxygen, you need 78 g of X.
For every one mole of oxygen you're using two moles of X so one mole of X weighs 39 g.
The relative atomic mass of X is 39.
You're very welcome
Perhaps I should dredge up all my old school and uni notes and write some chemistry hubs lol.
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