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How to concatenate rows in SQL server? – Concatenate Rows using FOR XML PATH()

Updated on September 27, 2014

Concatenation of several columns is easy and every can do. We have to use '+' and the column names to Concatenate. But how to do Concatenation among rows? Have you any idea? Yes, I am talking how to concatenating rows. I need couple of hours to figure out. I am not a SQL boss :) so, I need some time. Anyway, I solved this and feel to share all. Because I like to share my knowledge. :)

For this tutorial, we will use the AdventureWork2008R2 database. And I wan to use the tables [Production].[ProductCategory] and [Production].[ProductSubcategory] to display all the sub-category items under one category item. So, we need rows Concatenation. So, lets try.

I will break-down the whole problem into 3 steps:

  1. First, I want to show what are the outlook of those tables
  2. Now create a table which has category and subcategory using inner join
  3. Concatenation of rows to display the lists of subcategory under one category

Step 1: First, I want to show what are the outlook of those tables

We simply write the select query to display all the rows of [Production].[ProductCategory] and [Production].[ProductSubcategory] table

Query for ProductCategory table

select 
	* 
from 
	[Production].[ProductCategory]

Output of ProductCategory table

Query of ProductSubcategory table

select 
	* 
from 
	[Production].[ProductSubcategory]

Output of ProductSubcategory table

Step 2: Now create a table which has category and subcategory using inner join

Our required colums are category name and sub-category name column. So, if we create a natural join based on the ProductID then we can easily get the list of products-category and products-sub-category like column. So, lets do this

select 
	cat.Name [Category Name]
	,sub.Name [Sub-category Name]
from [Production].[ProductCategory] cat
	inner join [Production].[ProductSubcategory] sub
	on cat.ProductCategoryID = sub.ProductCategoryID

Output of inner join

Step 3: Concatenation of rows to display the lists of subcategory under one category

From the above pictures, we are seeing the lists of category name and subcategory name. But the category name is repeated and we don't want the repetition. Our goal is to display all the sub-category items under each category. So, we need to use FOR XMP PATH() to do this.

The sub-category items should be listed under the category item. So, the main table will be the [Production].[ProductCategory] table. Our final output should be 2 columns: category name and subcategory name. Form the table [Production].[ProductCategory] we can easily filter the category name and named it as Product Category. So, try to write the following query to display only the category name.

select 
	cat.Name
from 
	[Production].[ProductCategory] cat

Now, we will use for xml clause to retrieve select query result as XML format. So, the code should looks like the following:

select 
	cat.Name [Category Name]
	,(select sub.Name
	from [Production].[ProductSubcategory] sub
	where sub.ProductCategoryID = cat.ProductCategoryID
	for xml path('')
	)
from 
	[Production].[ProductCategory] cat

Our goal is to lists the output like a,b,c. So, we will use a trick. We will concatenate the subcategory with ,. So, the query looks like the following:

select 
	cat.Name [Category Name]
	,(select ',' + sub.Name
	from [Production].[ProductSubcategory] sub
	where sub.ProductCategoryID = cat.ProductCategoryID
	for xml path('') 
	)
from 
	[Production].[ProductCategory] cat

Now, delete the first , using the stuff function and name that column as Sub category. The final query should looks like the following:

select 
	cat.Name [Category Name]
	,stuff (
		(
			select ',' + sub.Name
			from [Production].[ProductSubcategory] sub
			where sub.ProductCategoryID = cat.ProductCategoryID
			for xml path('') 
		), 1, 1,''
	) [Sub category]
from 
	[Production].[ProductCategory] cat

And that's all following the above steps, we can easily concatenate rows. Hope, this is useful for new SQL developer. :)

working

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