What is the general term of 1,2,4,7,11,16,22?

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  1. profile image53
    michaelneLaposted 13 years ago

    What is the general term of 1,2,4,7,11,16,22?

    Is there any technique how to find the general term? plsss help me.

    1. Taiwo Oluwaseye profile image60
      Taiwo Oluwaseyeposted 5 years agoin reply to this

      Addition of 1 2 3 4 5 6 7......
      and so on

      1. Taiwo Oluwaseye profile image60
        Taiwo Oluwaseyeposted 5 years agoin reply to this


    2. kkapkaa profile image60
      kkapkaaposted 5 years agoin reply to this

      Fibonacci Sequence

      1. antbytes profile image60
        antbytesposted 3 years agoin reply to this

        The Fibonacci Sequence is the series of numbers: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... The next number is found by adding up the two numbers before it.

      2. learningradius profile image59
        learningradiusposted 3 years agoin reply to this

        It is not fibonacci series. Fibonacci series is like 0,1,1,2,3,5,8,13...... (adding adjacent number).
        The peculiarity of the question raised ( general term 1,2,4,7,11,16,22). Adding natural number to each of the terms in the series, we get the result.

        For people looking for UPSC Free Mock Test, visit https://learningradius.com/

  2. L.C. Smith profile image60
    L.C. Smithposted 13 years ago

    I'm not sure if this is a mathematical question, but it looks like you have posted a series of numbers that flow in the following way:
    1+1 = 2
    2+2 = 4
    4+3 = 7
    7+4 = 11
    11+5 = 16
    16+6 = 22

    1 was added to the 1st number to get 2, that sum, 2, was added to 2, because it was the second number, to get 4.  The sum of 4 was added to 3, because it was the third number, to get 7.  Yada, yada, yada...

    1. GoldyIndian profile image59
      GoldyIndianposted 8 years agoin reply to this

      I got suitable formulea for nth term and sum this type sequence and more sequence

  3. profile image53
    michaelneLaposted 13 years ago

    yah, but what is the exact formula to come up with this kind of problem.. thank you for your answer. ^^

  4. profile image52
    mathman32503posted 12 years ago

    To find the nth term of the sequence:

    0.5*n^2 - 0.5*n + 1

    If we look at the difference between successive terms, we see that the differences are not the same - so a linear function will not work.

    1  2  3  4  5  6   

    But if we look at the difference between successive differences (second-order differences, if you will), we see that these are the same - so a quadratic function will work.

    1  1  1  1  1  1     

    To find the function, I looked for some pattern.  I listed the triangular numbers (1 3 6 10 15 21 27); the nth triangular number is the sum of the positive integers less than or equal to n.  It appears as though the nth term of the sequence is adjusted down (by differing amounts) from the triangular number.  Specifically, to find the nth term, we subtract (n-1) from the nth triangular number. 

    This yields:

    (Sum of numbers 1 through n) - (n-1)

    = 0.5(n)(n+1) - n + 1               

    = 0.5*n^2 + 0.5*n - n + 1         

    = 0.5*n^2 - 0.5*n + 1

    I know that I've merely given you my thought process rather than a hard, fast method to be applied every time.  All I can say is that finding the nth term is like solving any other problem type: you get better with experience.  You build an intuition. 

    I hope this helps.

    1. GoldyIndian profile image59
      GoldyIndianposted 8 years agoin reply to this

      This is formula regarding to error method

  5. GoldyIndian profile image59
    GoldyIndianposted 9 years ago

    I have exact formulae
    But first I will regist it
    Cool my all Maths expert

  6. gmwilliams profile image84
    gmwilliamsposted 8 years ago


    I would call this a sequential equation e.g. 1,2,4,7,11,16,22, 29.  You see:
    22+7=29.....and 29+8=37, 37+9=46, the main component is adding sequential numbers to the equation.

  7. androidfan profile image64
    androidfanposted 8 years ago

    The simple formula of this number series is like that:-

    1st Digit + 1= 2nd Digit,
    2nd Digit + 2= 3rd Digit.
    3rd digit + 3= 4th Digit.

    So, Nth Digit = (N-1)th Digit + (N-1): It is the formula.

    So, if n=5, then the 5th Digit = (5-1)th Digit+(5-1)
                                                = 4th Digit + 4
                                                = 7+4= 11.

    1. GoldyIndian profile image59
      GoldyIndianposted 8 years agoin reply to this

      What is sum formulea Of this type sequence
      I got nth term formulea and sum formulea

  8. Soleman Ali profile image61
    Soleman Aliposted 7 years ago


  9. crowsnest profile image60
    crowsnestposted 6 years ago

    Xn = X(n-1) + (n-1) is the formula you are looking for.

    Where Xn is the nth (or general) term of the sequence.
    So, X(n-1) is the term directly before Xn.
    And (n-1) is just the integral value of n minus 1.

    Example: n=5
    Xn = 11
    X(n-1) = 7
    n-1 = 5-1 = 4

    So using the formula, 11 = 7 + 4

  10. profile image53
    arash prkposted 6 years ago

    1+0=1   1+1=2   1+3=4    ...

    general rule is :


  11. Taiwo Oluwaseye profile image60
    Taiwo Oluwaseyeposted 6 years ago

    1 2 4 7 11 16 22

    1st difference:  0 1 2 3 4 5 6 7.........

    16+6= 22
    22+7= 29

    And so .....

  12. MarieLB profile image77
    MarieLBposted 6 years ago

    next comes 29
    Each time you add up one more than the last time.
    So  to the first no ie:  1  you add 1
    Then you add 2,3,4,5,6,7

  13. profile image53
    Oluwaseyetposted 6 years ago

    Yes there is a technique it is called Quadratic Sequence

                                                     1,2,4,7, 11, 16,22

    Difference 1 2 3 4 5 6
    And so on

  14. soumya reddy profile image60
    soumya reddyposted 5 years ago

    1,2,4,7,11,16,22 next one is 29. check it once http://bit.ly/2pHf8sk

  15. profile image60
    Unogeeksposted 19 months ago

    next is 29 get solution here https://bit.ly/3MaYBTn

  16. profile image60
    paulspavanposted 17 months ago

    Communications link failure by Mulesoft 4.x only in localhost

    I'm using mulesoft 4.x. I have the following problem: I can't get it to connect to mysql server in localhost, but I can get it to connect on remote hosts without problem. However, that server "localhost" works correctly so much that it is reachable by the mulesoft runtime if I move it to another machine.

    the error is: Caused by: org.mule.runtime.extension.api.exception.ModuleException: java.sql.SQLException: Cannot get connection for URL jdbc:mysql://localhost:3306/test?logger=org.mule.extension.db.api.logger.MuleMySqlLogger : Communications link failure

    Example: VM with ip and mulesoft runtime installed with MYSQL. mulesoft does not connect, but if I move mulesoft to a different server with ip, it connects to Mysql on

    please advise


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