Calculate the molecular mass for the gas... Please.When 1.40g of an unknown gas is held in an otherwise empty 800 mL container, the pressure is 1159 mmHg at 25 oC.
Assuming an ideal gas: PV = nRTWhere P = pressure, V = volume, n = number of moles, R is the ideal gas constant, T is temperatureP = 1159 torrV = 0.800 LR = 62.364 L*torr/(mol*K)T = 298.15 Kn is unknown, so solving for n gives usn = PV/(RT) = 1159 * 0.800/(62.364*298.15) mol = 0.0499 moles of gas.We know that this many moles weighs 1.40 g, so the molecular weight is 1.40 g/0.0499 mol = 28.1 g/mol.
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