Why only around 11% of an iceberg is above water, while the rest of ice is hidden?
Hint: the density of see water is 1030 kg/m3, the density of ice is 920 kg/m3.
Floating objects displace amount of fluid equal mass of floating object. This creates enough buoyancy to keep an object afloat. Since the density of iceberg is about 90% of seawater density, approximately 90% of iceberg will be under water in oredr to displace enough water.
Great explanation Glasso! It is worth mentioning that this fact is described by the Archimedes's principle. In this particular case, buoyant force Fb acting on around 90% of the iceberg balances gravity force Fg on the iceberg. More precisely, from Fb = Fg if follows ρ * g * (V / x) = m * g where is the density of water, g gravitational acceleration, V is the volume and m mass of the iceberg. A short calculation gives result.
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