Given that the square root of

b^2 + 4ac = c + a for any three consecutive Fibonacci numbers a,...

an algebraic proof is needed here.You're difficult for this early Sunday morning 2:40 PM . I was very good in algebra thousand years ago! Though, I don't remember to work with Fibonacci numbers.... :-|

Related Discussions

- 2
### Prove that for any four consecutive Fibonacci numbers a, b, c, d, the square roo

by pemekwulu7 years ago

Prove that for any four consecutive Fibonacci numbers a, b, c, d, the square root of a^2 + 4bc...is always a perfect square whose square root is equal to d.

- 2
### If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in t

by pemekwulu7 years ago

If a, b, and c are consecutive Fibonacci numbers and a^2 + 4bc = 64, find a in terms of b and c.Fibonacci numbers are numbers of the form: 1, 1, 2, 3, 5, 8, 13, 21, 34, x, y, x+y.............

- 5
### How do you do square root?

by Liz Elias4 years ago

How do you do square root?Sometimes, the answer is obvious, such as 3 being the square root of 9. However, I was never able to understand how the square root operation is any different from regular division, given...

- 2
### Indices and Surds : Please explain the concept simply and easily

by shazwellyn5 years ago

Indices and Surds : Please explain the concept simply and easily

- 3
### How Do You Calculate Moving Average?

by ngureco5 years ago

How Do You Calculate Moving Average?A moving average is also the rolling average, rolling mean or running average. What difference is there between a simple moving average, cumulative moving average, and weighted moving...

- 4
### math class what is the square root of 1246842646642824682

by tyrelle6 years ago

math class what is the square root of 1246842646642824682

Copyright © 2018 HubPages Inc. and respective owners.

Other product and company names shown may be trademarks of their respective owners.

HubPages^{®} is a registered Service Mark of HubPages, Inc.

HubPages and Hubbers (authors) may earn revenue on this page based on affiliate relationships and advertisements with partners including Amazon, Google, and others.

terms of use privacy policy (0.49 sec)

working